25=40t-16t^2

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Solution for 25=40t-16t^2 equation: 



25=40t-16t^2

We move all terms to the left:

25-(40t-16t^2)=0

We get rid of parentheses

16t^2-40t+25=0

a = 16; b = -40; c = +25;
Δ = b2-4ac
Δ = -402-4·16·25
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$t=\frac{-b}{2a}=\frac{40}{32}=1+1/4$

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